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90^2+90^2=x^2
We move all terms to the left:
90^2+90^2-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+16200=0
a = -1; b = 0; c = +16200;
Δ = b2-4ac
Δ = 02-4·(-1)·16200
Δ = 64800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{64800}=\sqrt{32400*2}=\sqrt{32400}*\sqrt{2}=180\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180\sqrt{2}}{2*-1}=\frac{0-180\sqrt{2}}{-2} =-\frac{180\sqrt{2}}{-2} =-\frac{90\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180\sqrt{2}}{2*-1}=\frac{0+180\sqrt{2}}{-2} =\frac{180\sqrt{2}}{-2} =\frac{90\sqrt{2}}{-1} $
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